Question

A 3.25g sample of calcium carbide, CaC2, reacted with water to produce acetylene gas, C2H2 and calcium hydroxide. If the acetylene was collected over water at 17C and 0.974atm, how many mL of acetylene were produced?
CaC2 + H2O  C2H2 + Ca(OH)2

Answer 1

What was the temperature that was used to do the calculation?
17K
290K
280K
273K

Answer 2

use molar mass to find moles
3.25 g CaC2 @ 64.10 g/mol CaC2 = 0.0507 moles CaC2

by the equation:
1 CaC2 & 2 H2O --> Ca(OH)2 & 1 C2H2
0.0507 moles CaC2 produces an equal number of moles of C2H2 = 0.0507 moles C2H2
PV = nRT
( 0.955 atm) (V) = (0.0507 moles C2H2) (0.08206 L-atm/mol-K)(290 Kelvin)

Answer 3

290k

Answer 4

okay i thought so but i wasn't sure. i have a couple other questions could you check my answers?

Answer 5

sure

Answer 6

Thank you so much nobody would help me last night when i posted it the first time. I'll put the other questions up.

Answer 7

no problem if I am on just tag me I will help you

Answer 8

What coefficients balance the reaction?
A.1,1,1,1
B. 1,2,2,1
C. 1,2,1,1
D. 2,2,1,1
I chose B. Is that right

Answer 9

correct

Answer 10

I have 2 more questions that go with this could you look at them too? And yay i got one right

Answer 11

cool and sure

Answer 12

How many moles of C2H2 were used in the PVnRT equation?
A. 0.1 mol CaC2
B. 0.13 mol C2H2
C. 0.05 mol C2H2
D. 3.25 mol CaC2
I chose C.

Answer 13

What is your final answer in mL?
A. 1.22mL
B. 0.0012mL
C. 1220mL
D. 1220L
i chose C.

Answer 14

give me a sec to check them

Answer 15

no problem

Answer 16

I got the same

Answer 17

okay thanks again. i have 2 other questions i need to post.

Answer 18

sure