Use the slope of 2 and point (-6, -3) to graph the line.

Question

anonymous · Answer

https://gyazo.com/2bc582e97ca6ecc196b49849d0787c7b https://gyazo.com/1eeed072c89796ba9b09c71a83f60f34 https://gyazo.com/d223384cb828d4b6b4580bf581a8646d https://gyazo.com/a54874ac515a4b20f4f4531f87f409e8

anonymous · Answer

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priyar · Answer

$$(y-y1)/(x-x1) = m$$ where m is the slope..

priyar · Answer

the point (x1,y1) has already been given to u

priyar · Answer

what r u getting @Lelenny?

anonymous · Answer

So I just need to plug in the numbers?

anonymous · Answer

(-3 - -3(1)) / (-3 - -3(1))

trojanpoem · Answer

No , let point (x,y) be on the line

use the formula of slope

dy/dx = slope

slope = 2
point (-6,-3) , (x,y)
and find the equation
then turn it into
y = mx + b (slope-intercept) and graph using x ,y intercept

anonymous · Answer

Still a little confused.

trojanpoem · Answer

-3 - y/ -6 - x = 2

3+y/6+x = 2

3+y = 12 + 2x

y = 2x + 9

y-intercept : 9

x intercept : -9/2

|dw:1452702359523:dw|

anonymous · Answer

So therefore, it's " https://gyazo.com/2bc582e97ca6ecc196b49849d0787c7b " , correct?