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Mathematics 7 Online
OpenStudy (anonymous):

What is the slope and y-intercept of line q graphed below? A. 3 and (-3, 0) B. 3 and (0, 1) C. 1/3 and (0, 1) D. 1/3 and (-3, 0) graph below

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@daisyrainbowmist

OpenStudy (anonymous):

oh gosh im not good at math I wish I can help but I don't know what the answer would be

OpenStudy (anonymous):

The graph of a first degree polynomial is always a straight line. The graph of a second degree polynomial is a curve known as a parabola. A polynomial of the third degree has the form shown on the right. Skill in coördinate geometry consists in recognizing this relationship between equations and their graphs. Hence the student should know that the graph of any first degree polynomial y =ax + b is a straight line, and, conversely, any straight line has for its equation, y =y + g

OpenStudy (anonymous):

im sorry i dont understand some of that.

OpenStudy (priyar):

@jewelry02 just find two points where the line intersects the axes

OpenStudy (anonymous):

-3 and 1

OpenStudy (anonymous):

but thats not an answer

OpenStudy (anonymous):

Thats hint

OpenStudy (anonymous):

@priyar

OpenStudy (anonymous):

Not givin answer :|

OpenStudy (priyar):

ya that was just a start...

OpenStudy (anonymous):

oh

OpenStudy (priyar):

u mean (-3,0 ) and (0,1) right?

OpenStudy (anonymous):

its not 1?

OpenStudy (priyar):

y-intercept is the length from origin to the point where the line meets the y-axis

OpenStudy (priyar):

so what will the y-intercept be?

OpenStudy (anonymous):

its D

OpenStudy (anonymous):

right?

OpenStudy (priyar):

how?

OpenStudy (priyar):

in option D y takes value zero so its point of x-intercept..

OpenStudy (anonymous):

well its definently not b or c

OpenStudy (priyar):

what makes u think so?

OpenStudy (anonymous):

guys can you just help her poor thing she dosent know the answer

OpenStudy (anonymous):

because they are positive

OpenStudy (priyar):

so what..here the graph cuts y axis at 1 so the point is (0,1)...that rounds it off two b or c

OpenStudy (priyar):

to find the answer we must find the slope..

OpenStudy (anonymous):

and we can do that by?

OpenStudy (priyar):

we have 2 points that i wrote above..use that in the below formula

OpenStudy (priyar):

\[slope=y1-y2/x1-x2\]

OpenStudy (priyar):

where (x1,y1) and (x2,y2) represent two points

OpenStudy (priyar):

just plug in the values

OpenStudy (anonymous):

I'm sorry but i don't know what points and where i put them. i don't know what the 1's are for. i just nevermind can you let me know where they go at least?

OpenStudy (priyar):

ok let me do this one for you as an example: \[0-1/-3-0\]

OpenStudy (priyar):

i got this coz these were our points: (-3,0 ) and (0,1)

OpenStudy (anonymous):

.333333....

OpenStudy (priyar):

or in a simpler way:1/3!!

OpenStudy (priyar):

so which option is it?

OpenStudy (anonymous):

i said D you never said whether it was right or wrong

OpenStudy (priyar):

its wrong..

OpenStudy (priyar):

we got slope:1/3 and the y intercept point:(0,1) then how can it be D??

OpenStudy (anonymous):

then is it B

OpenStudy (anonymous):

C

OpenStudy (priyar):

good!

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