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OpenStudy (michele_laino):
where is the question, please?
OpenStudy (michele_laino):
in order to compute the requested area, we have to subdivide such polygon into more triangles or rectangles, like below:
OpenStudy (michele_laino):
as we can see , I have subdivided such polygon, into four tringles and one rectangle
OpenStudy (michele_laino):
now, for example, the area of traingle T1, is:
\((3 \times 1) /2=...?\)
OpenStudy (shaleiah):
1.5
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OpenStudy (michele_laino):
ok!
area of T2:
\((5 \times 1)/2=...?\)
OpenStudy (shaleiah):
2.5
OpenStudy (michele_laino):
ok! Next:
area of T3
\((4 \times 1)/2=...?\)
OpenStudy (shaleiah):
2
OpenStudy (michele_laino):
then, area of T4:
\[\frac{{4 \times 3}}{2} = ...?\]
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OpenStudy (shaleiah):
6
OpenStudy (michele_laino):
and area of rectangle R1:
\[3 \times 4 = ...?\]
OpenStudy (shaleiah):
12
OpenStudy (michele_laino):
great!
So, the area of the polygon, is:
\(1.5+2.5+2+6+12=...?\)
OpenStudy (shaleiah):
24
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OpenStudy (michele_laino):
that's right! :)
OpenStudy (michele_laino):
yes! Please look at this drawing:
OpenStudy (michele_laino):
first step:
the area of the rectangle ABCD, is:
\[7 \times 4 = ...?\]
OpenStudy (shaleiah):
28
OpenStudy (michele_laino):
great!
now, we have to compute the areas of each of triangles T1, T2, and T3
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OpenStudy (michele_laino):
so, area of T1:
\[\frac{{4 \times 2}}{2} = ...?\]
OpenStudy (shaleiah):
4
OpenStudy (michele_laino):
ok!
area of T2:
\[\frac{{7 \times 3}}{2} = ...?\]
OpenStudy (shaleiah):
10.5
OpenStudy (michele_laino):
then area of triangle T3:
\[\frac{{5 \times 1}}{2} = ...?\]
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OpenStudy (shaleiah):
2.5
OpenStudy (michele_laino):
correct!
Now, the area of the blue triangle, is given by subtracting, from the area of the rectangle ABCD, the areas of each triangles T1, T2, T3, namely, we have to do such computation:
\(28-(4+10.5+2.5)=...?\)