Question

I will give a metal to whoever helps me!!!!!
Aluminum granules are a component of some drain cleaners because they react with sodium hydroxide to release both energy and gas bubbles to help clear the drain clog. The reaction is:
NaOH + Al + 6H2O  2NaAl(OH)4 + 3H2
What mass of aluminum would be needed to produce 4L of hydrogen gas at 101kPa and 25C?

Answer 1

What value of R is used when solving the PVnRT equation?

Answer 2

@Missiey

Answer 3

1. You know how much H2 gas was produced Use Ideal Gas Law to solve for moles
PV = nRT

https://en.wikipedia.org/wiki/Ideal_gas_law

Make sure you use an R that has the same units as what you input into the equation

Answer 4

You want to use a Value of R that has units that are compatible with the values units you input into the Ideal Gas Law

You can either convert your units to those that match the R constant or you can convert the R constant. I just convert the units normally

If you need a guide on unit cancellation this does a really good job

http://www.purplemath.com/modules/units.htm

Answer 5

http://mutuslab.cs.uwindsor.ca/schurko/introphyschem/handouts/gasconstant.pdf

Answer 6

so you know for hydrogen:

P = 101kPa
T = 25C
V = 4L
n = ?

A) First you always want to convert celsius to kelvin (It is the si temperature scale and it only goes to 0 (normally)) unless otherwise told to (which is a few rare cases in phys chem)

To convert celsius to kelvin just add 273 for instance:

530Degrees C + 273 = 303K

B) you want to use an R constant that has at least two of these units in it so you have kPa, K, and L

I would use 8.20578 x 10^(-2)L*atm/(K*mol)

Notice that the pressure is atm so you will need to convert kPa to atm to use this constant.

just type in google 1 atm to kPa to develop the formula to cancel the units.

2. The next thing you want to do is always divide (the moles) by the number in front of the chemical species you start from (in your case hydrogen) in the chemical equation and multiply by the number in front of the one you are converting to (In this case aluminum).

Answer 7

let me know if this is helpful

Answer 8

@Australopithecus im totally lost. I'm not very good at chemistry.

Answer 9

@Missiey can you look at this question for me please.