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Mathematics 7 Online
OpenStudy (anonymous):

Need Help with liberal Arts math! Can anyone help?

OpenStudy (anonymous):

ill try to help u

OpenStudy (xapproachesinfinity):

ok so what is the question?

OpenStudy (anonymous):

Alright let me type this down...sorry.

OpenStudy (anonymous):

Simplify the expression and rewrite in rational exponent form.

OpenStudy (anonymous):

Im simplifying it slowly...so far i got x^3/2*24y*y^3/4 over 3x^1/2* 4x^2/3

OpenStudy (anonymous):

@xapproachesinfinity I honestly dont know what to do next.

OpenStudy (xapproachesinfinity):

sorry i was away :(

OpenStudy (xapproachesinfinity):

okay let us see what do we have here

OpenStudy (xapproachesinfinity):

ok so far good start

OpenStudy (xapproachesinfinity):

first simplify the bottom more

OpenStudy (xapproachesinfinity):

you have x^something times x^ another thing see you add up the power following this rule \[a^na^m=a^{n+m}\]

OpenStudy (anonymous):

Can i say what i got for my answer? I got, X^5/3 Y^3/4 over 2?

OpenStudy (xapproachesinfinity):

seems wrong!!

OpenStudy (xapproachesinfinity):

let's how it is done!

OpenStudy (anonymous):

Alright, let me retry this sorry, its hard im juggling a lot of work...

OpenStudy (xapproachesinfinity):

\[\frac{24x^{\frac{3}{2}}yy^{\frac{3}{4}}}{12x^{\frac{1}{2}}x^{\frac{2}{3}}}=\frac{2x^{3/2}y^{7/4}}{x^{7/6}}\]

OpenStudy (xapproachesinfinity):

i used the property described above

OpenStudy (xapproachesinfinity):

when the base is the same you add up the exponents

OpenStudy (xapproachesinfinity):

then you need one more property to simply more x^n/x^m=x^n-m

OpenStudy (anonymous):

Okay so for once of my answers could it be 2x^1/3y^7/4?

OpenStudy (anonymous):

Also I hope you dont mind helping me with a couple more...im really confused.

OpenStudy (xapproachesinfinity):

actually it is the answer

OpenStudy (anonymous):

You're joking... Wow!! Your explanation helped a ton...can you help me with some more? Maybe like one or two more? :/

OpenStudy (anonymous):

Thank you so much, your helping my brain out :)

OpenStudy (xapproachesinfinity):

sure :)

OpenStudy (anonymous):

same thing for this one.

OpenStudy (anonymous):

\[7c \sqrt[3]{d^5}\]

OpenStudy (anonymous):

That was my answer...

OpenStudy (xapproachesinfinity):

excellent!!

OpenStudy (xapproachesinfinity):

any others?

OpenStudy (anonymous):

REALLY?! I just scribbled on that one. literally took me a week. yes about two more.

OpenStudy (xapproachesinfinity):

ok

OpenStudy (xapproachesinfinity):

once you get this it takes no time

OpenStudy (anonymous):

Assume a and b are nonzero rational numbers and c is an irrational number. for each following expression determine whether the result is rational, irrational or both.

OpenStudy (anonymous):

Let me put the other part down

OpenStudy (xapproachesinfinity):

ok

OpenStudy (anonymous):

Part A: a(b+c) Part B: \[(a \sqrt{7})^2\] Part C: ab+ab^2

OpenStudy (anonymous):

Now looking at part A i believe its rational

OpenStudy (xapproachesinfinity):

let's see we know a and b are rational and c irrational we start with b+c rational added to irrational the result will be irrational

OpenStudy (anonymous):

and a rational multiplied by an irrational gives us an irrational?

OpenStudy (xapproachesinfinity):

then if you multiply irrational with rational you will still get irrational take an example pi add 3 3+pi if you multiply you get 2(3+pi)=6+2pi which is still irrational

OpenStudy (xapproachesinfinity):

yes

OpenStudy (xapproachesinfinity):

Part b is easy

OpenStudy (anonymous):

Alright now for part...B..im going to look this one over quick

OpenStudy (xapproachesinfinity):

ok i will let you that one let's how you argue it rationality

OpenStudy (anonymous):

Looking through my notes it looks like it would be rational but then again, i could be wrong because of the square root of 7...that leaves a decimal that doesnt repeat a pattern, let me check again..

OpenStudy (xapproachesinfinity):

on it can be proven that if a is rational (sqrta)^2 is rational too obviously a=(sqrta)^2

OpenStudy (anonymous):

Yup it doesnt have a pattern to it and it doesnt end.

OpenStudy (anonymous):

so does that mean it would be rational?

OpenStudy (xapproachesinfinity):

not that(sqrt7)^2 is a perfect square

OpenStudy (anonymous):

now thinking about it, could it actually be both?

OpenStudy (xapproachesinfinity):

don;t be confused sqrt7 by itself is irrational but with square the square root cancels

OpenStudy (anonymous):

Oh so it is rational because of the ^2

OpenStudy (xapproachesinfinity):

no it cannot be either rational or irrational there is no such thing as both

OpenStudy (xapproachesinfinity):

exactly!

OpenStudy (xapproachesinfinity):

so (a sqrt7)^2=a^2(sqrt7)^2 since both a^2 and (sqrt7)^2 are rational the entire # is rational

OpenStudy (xapproachesinfinity):

i i guess last is most easier just product and addition of rational numbers

OpenStudy (anonymous):

Thank you again! Your literally a life saver, Alright Part C...

OpenStudy (xapproachesinfinity):

it can be easily seen what it is

OpenStudy (anonymous):

This looks like its rational. :)

OpenStudy (xapproachesinfinity):

yes it is

OpenStudy (xapproachesinfinity):

just additioon and product of numbers that are rational

OpenStudy (xapproachesinfinity):

no problem, glad i was of help

OpenStudy (anonymous):

Alright, Just one more but im pretty sure i can handle it. I dont know if you want to take a look.

OpenStudy (xapproachesinfinity):

make it quick i need to go :)

OpenStudy (anonymous):

Okay find the value of ____ and place it in simplest form.

OpenStudy (anonymous):

Im pretty sure this one is irrational as well.

OpenStudy (xapproachesinfinity):

but the question is not asking for that?

OpenStudy (anonymous):

thats the second part of that

OpenStudy (anonymous):

sorry i forgot to add that.

OpenStudy (xapproachesinfinity):

ok that is most simple form and it is rational 0.22 recurring is rational but radical 112 is not rational

OpenStudy (xapproachesinfinity):

that's allright?

OpenStudy (anonymous):

Alright, so that would still mean its irrational correct?

OpenStudy (xapproachesinfinity):

yes

OpenStudy (anonymous):

Woo!! Thank you so much! I owe you one :)

OpenStudy (xapproachesinfinity):

my pleasure! i happy if y learned enough from me:)

OpenStudy (anonymous):

I did thank you thank you thank you :)

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