Question

Variable y varies directly with x^2, and y = 96 when x = 4

What is the value of y when x = 2?

Y =

Answer 1

I already did some of it but the end is confusing I already did this

Y = kx^2

K = y/x^2

K = 96/4^2

But I don't know how to substitute 96 for y and 4 for x

Answer 2

your next step is to evaluate `96/4^2`

Answer 3

keep in mind that PEMDAS says you have to do the exponents first, then division comes after (since the E for exponent comes before D for division)

Answer 4

Okay thanks

Answer 5

let me know what you get

Answer 6

I'm still confused I can't solve it @jim_thompson5910

Answer 7

so you are not able to evaluate what `96/4^2` is equal to?

Answer 8

does it help if I replaced the `4^2` with `16` ?

so `96/4^2` turns into `96/16` which becomes what?

Answer 9

No i don't know how

Answer 10

Yeah I'll try again

Answer 11

what is 96/16 equal to?

Answer 12

6?

Answer 13

yes, k = 6

Answer 14

so `y = k*x^2` turns into `y = 6*x^2`

Answer 15

now plug `x = 2` into `y = 6*x^2`

Answer 16

Y = 6*x^2 so y = 24?

Answer 17

correct

Answer 18

don't forget to show the step `y = 6*2^2`

Answer 19

Thank you!!!!!!

Answer 20

you're welcome