Question

Please check my work :) Evaluating integrals

Answer 1

\[\int\limits_{0}^{3}2\left| x^2-4 \right|dx\]

Answer 2

In the end I got = 19
If that's incorrect I could write out my entire process :)

Answer 3

You need to evaluate this in intervals.

Answer 4

\[\int\limits_{0}^{2}2(4-x^2)+\int\limits_{2}^{3}2(x^2-4)\] this is how I did it :) is that correct?

Answer 5

Well done!

Answer 6

And the answer does come out to 19?

Answer 7

Let me check that. You process is right.

Answer 8

I don't think it's 19

Answer 9

hmm
\[8x-(2x^3)/3 \] evaluated at a=0, b=2
\[(2x^3)/3-8x\] evaluated at a=2, b = 3

Answer 10

= 8+(3-(-8)) = 19

Answer 11

For case 1

8*2-2*2^3/3
16-16/3
16(1-1/3)
16(2/3)
32/3

Answer 12

oh woah I think I went off on the 2*x^3 part. woops.

Answer 13

46/3 is it?

Answer 14

Yes

Answer 15

Now it is done ;)

Answer 16

Yay!! thank you so much :)
I think I had dropped the 2 on accident o.o

Answer 17

Yall are life savers heh

Answer 18

Accidents doe >.>

Answer 19

Ikr :| the ones that change your grade by a whole letter hahah

Answer 20

:| Exactly

Answer 21

smh. Well thanks again:) I only have one left kekek. I will probably post it in a new question soon.