Check my answers? http://prntscr.com/9pw7iz http://prntscr.com/9pw7t5
5) correct
6)correct well done
ok ty, are 9 and 10 also correct?
10 is, 9 is not.
10) correct 9) check again
I had trouble with 9, can you help me answer it?
Sure!
\(\bf\Large \frac{a}{b} \div c = \frac{a}{b} \times \frac{a}{c}\) Do you understand that?
Please, instead of just asking others to respond "correct" or "incorrect," explain how you got your results. Then others could give you far more meaningful feedback.
yes i do understand it so, my answer would be option B
That's correct! :)
ok ty, i forgot to put question 7 and 8 these are it http://prntscr.com/9q1bkd can you just take a quick look?
Question #7 is correct!
Question #8 is also correct!
ty so much
You're welcome!!
@MeganXOXO you wrote earlier that \[\frac{a}b\div c=\frac{a}b*\frac{a}c\] that is NOT correct as you will see if you try it with some real numbers. let's try \[a=8,\ b=2,\ c=3\]\[\frac{8}2\div3=\frac{8}2*\frac{8}3\]\[4\div3 = \frac{64}6\]nope! the correct statement is \[\frac{a}b\div c=\frac{a}b\div\frac{c}1=\frac{a}b*\frac{1}c\] to divide by a fraction, invert the denominator fraction (aka take its reciprocal) and multiply the numerator fraction and the denominator fraction. Any quantity which is not in fractional from can be made into a fraction by using the quantity as the numerator and \(1\) as the denominator.
@whpalmer4 Oh, yes. My bad. That is a mistake on my part. Thank you for catching it! :-)
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