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What values of x satisfies log2(3x) + log2(2x) = 3?
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log a + log b = log (a*b) so in this case log (3x) + log (2x) = log (6x^2) = 3
How do I deal with the log base 2
base of log is irrelevent: logn (x) = m means n^m = x
Ahhhhhh I got it
Okay, similar to @MrNood \[\log_{2} (3x)+\log_{2} (2x)=3\] Using the identity: loga+logb=log(a*b) \[\log_{2} (6x^2)=3\]
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good job then. :)
I just forgot all the identities, that's all
log2(6x^2) = 3 2^3 = 6x^2 4/3 = x^2
Mmm I see, thanks
yep, do you know how to simplify ur answer?
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unless that answer format is accepted
Yea x = (4/3)^(1/2)
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