Question

How did they get this?
(Algebra 2) (Subtracting radical expressions)

Answer 1

8.5-45.2

Answer 2

18=3*3*2...so u can take 3 outside the root

Answer 3

i think ive never done this i dont think, so dont count on me

Answer 4

i gotchu bro.

Answer 5

similarly do for 32 @-Welp-

Answer 6

since both numbers have different square roots, you want both numbers to have the same square root in order to subtract them.

Answer 7

@-Welp- ? what are u getting?

Answer 8

looking at the square roots of 18 and 32. What number do they both have in common for multiplication? As in, what one number that multiplies into 18 and 32 as well.

Answer 9

The goal of the original equation are for both numbers to have the same square roots in order to get subtracted. Numbers with different square roots cannot be subtracted, hence the reason.

Answer 10

Good so far?

Answer 11

\[2\sqrt{3*3*2}=2*3\sqrt{2}\]

Answer 12

do u know this @-Welp- ?

Answer 13

so the first term has become \[6\sqrt{2}\]

Answer 14

\[\sqrt{32}=\sqrt{16*2}=4\sqrt{2}\]

Answer 15

so 8*4root2= 32root2

Answer 16

\[6\sqrt{2}-36\sqrt{2}\]

Answer 17

now just subtact this what do u get @-Welp- ?

Answer 18

Back. "do u know this @-Welp- ?" No, how did you take out the 3s?

Answer 19

\[\sqrt{3*3}=3\]

Answer 20

its the reverse of 3^2

Answer 21

Oh

Answer 22

ok now go through the other steps i have written..and tell me if u have a problem

Answer 23

So you just multiply the same numbers inside of a square root? I noticed you left the 2 inside of the square root alone.

Answer 24

its not 2*2 so i left 2

Answer 25

so whats the answer..did u subtact @-Welp-

Answer 26

I'm supposed to show my work. Is this right or did I miss a step?
\[2\sqrt{18}- 5\sqrt{32}\]
\[= 2\sqrt{3*3*2}- 5\sqrt{16*2}\]
\[= 2*3\sqrt{2}- 5*4\sqrt{2}\]
\[6\sqrt{2}-20\sqrt{2}\]
\[=-14\sqrt{2}\]