PLEASE HELP **MEDAL AND FAN** Solve, using the substitution method. 2x + 3y = 1 y = x – 8 Question 3 options: (0, –8) (2, –6) (4, –4) (5, –3)
Choose one equation from each pair and solve for y. Then substitute that y into the second equation. IE 3x+y=4 x+2y=7 Solving for y the first equation becomes y=-3x+4. Plug that in for y in the second equation: x+2(-3x+4)=7 Simplify for x. -5x=1 x=-1/5 choose one of original equations and plug in x and solve for y. 3(-1/5)+y=4 y=23/5
Post one question at a time, please. Have you used the substitution method before? If so, describe what you did and why.
It is one question? @mathmale
Then, ask yourself: "What would be a suitable substitution to use in Problem 1?"
Yes, you're right; it is just one question. Sorry. :(
Its fine!
kylie i answered your question its at the top
I didnt understand it so then whats the answer? @Cj_2COOL
-x+3y=4 x+6y=14 Take an equation: x + 6y = 14 Then make it equal x. x + 6y = 14 - 6y -6y x = - 6y + 14 Then plug x into the first equation that was not used: -(- 6y + 14) + 3y = 4 6y - 14 + 3y = 4 9y - 14 = 4 +14 +14 9y = 18 /9 /9 y = 2 Then plug y into either equation -x+3y=4 -x + 3(2) = 4 -x + 6 = 4 -6 -6 -x = -2 /-1 /-1 x = 2 The solution for the first problem is x = 2 and y = 2
Thanks for your input, @Cj_2COOL , but next time do NOT do the problem for the other person; instead, provide structure and guidance so that that person can find his or her own answer.
Thank you for both of your help but i think i found the answer is it D?
I'd be glad to respond if you'd share your work first. Need to know how you decided upon an answer.
Sorry mathmale ill remember that
:)
I just thought of (x,y) replace the #'s in with x,y
But you're supposed to use substitution specifically. You will be asked in the future to use this method. You are given 2 equations. Which one has already been solved for y?
The second one
right. That equation states that y is the same as (x-8). Throw out y in the first equation and replace it with (x-8). (You must keep those parentheses.) Show your results.
\[2x+3y=1\rightarrow 2x + 3( ?? )=1\]
Thank you for everything but its fine!
Sorry, but I need to get off the 'Net. Bye.
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