Question

which relation is a function?

A. {(-3,2),(-2,3),(-1,2),(0,4),(1,1)}
B. {(-3,2),(-2,3), (-1,1),(0,4),(0,1)}
C. {(-3,2),(-1,3),(-1,2),(0,4),(1,1)}
D. {( -3,3),(-2,3),(-1,1),(0,4),(0,1)}

Answer 1

A function is where the set of ordered pairs that have an input and output c:

Like this

Answer 2

BUT

Answer 3

For each set of ordered pairs, look to see if any of them have the same \(x\) value more than once. If not, that relation is a function. However, if the same \(x\) value does repeat, then you must look to see if it always has the same \(y\) value. If it does, that relation is a function; if there are multiple \(y\) values associated with a single \(x\) value, it is not a function.

Answer 4

It is NOT considered a function, if two points in the set of ordered pairs have the same x.

Answer 5

What whpalmer said cx

Answer 6

So it is B?

Answer 7

@ChantySquirrel1129** no, that is not correct. You can have multiple copies of the same \(x\), but you must then always have the same \(y\).

Answer 8

in other words, you can have duplicate points and still have a function.

Answer 9

Chanty I have my question up why arent you there?

Answer 10

Oh, let me explain better, I mean that if they have the same x, but different ys, then it's not considered a function c:

Answer 11

;c

Answer 12

Let me go to your question then, mommasboi cx

Answer 13

@XxMommasBoixX Look at it this way: pretend you have a list of people who are allowed to attend a party. That list also has the name of that person's date. You can list the person several times, but they can only bring one person to the party.

Answer 14

Each value of \(x\) only gets to bring one date (a value of \(y\)). No posses allowed :-)

Answer 15

so it is B?

Answer 16

{(-3,2),(-1,3),(-1,2),(0,4),(1,1)}

here we have two ordered pairs where the value of \(x\) is identical (\(-1\)) but they do not have the same value of \(y\). not a function

{( -3,3),(-2,3),(-1,1),(0,4),(0,1)}

here we have two ordered pairs where the value of \(x\) is identical (\(0\)) but they do not have the same value of \(y\). not a function

{(-3,2),(-2,3),(-1,2),(0,4),(1,1)}

all the values of \(x\) are different, so there is no problem. this is a function

{(-3,2),(-2,3), (-1,1),(0,4),(0,1)}

here we have two ordered pairs where the value of \(x\) is identical (\(0\)) but they do not have the same value of \(y\). not a function

I have mixed up the order, so you should repeat this process on your own to find the right answer.