How long does it take to triple an investment of $23360 if the investment pays only simple interest at the rate of 5.18% per annum?
wait...
so our principal is 23360?
@mathmale
Where do I start? Ask me questions that lead me to the solution.
Use this equation.... Future Value = Present Value ( 1 + Interest Rate ) ^ N you know everything except N, so solve for N. Is this clear?
Yes, I've been using that equation for this hw. However, I am having difficulty determining what P and F are. What is principal? Money you start with? The money you barrow or loan?
Those are good questions. You want a investment of $23360 to triple in value, so ideally you know the PV is 23360 and the FV is three times that or 70080. However it is just FV/PV=3 so the equation becomes.... 3= (1+IR)^N
I had it setup like this 70080 = 23360(0.0518)*n solve for n Why is it FV/PV? Is it a ratio?
oh shoot that is the same equation.
oh wait I didn't use the compound interest formula...
To solve your equation divide both sides by 23360. Also you forgot the 1 in (1+0.0518),
Well I thought we were looking at simple interest that is why I used F = P*i*n
because it says simple interest
Oh, I think you are right. It does say simple interest rate. I was thinking it was simple because it wasn't compounded monthly.
okay cool
I got n = 57.91 years
so about 58 years if we round
but it says "simple interest at the rate of 5.18% per annum" so is the interest calculated per annum and added in or not. Did they given an answer for this question? I got the 57.91 year simple interest and around 21.74 years compounded yearly.
no, I can find out now. I only get three attempts for each hw problem. Let me check because this was my last problem.
nope not correct
Well the question changed.... How long does it take to quadruple an initial investment of $40738 if the investment pays only simple interest at the rate of 10.97% per annum?
Try this and see if you get the right answer... log(4) / log (1.1097) = 13.318 years How accurate do they want you to be? How many decimal points?
If the answer is right I can explain it to you.
Is this to the original question or the current question. After I attempt the hw once all the questions change. So I need help with this one How long does it take to quadruple an initial investment of $40738 if the investment pays only simple interest at the rate of 10.97% per annum?
My previous answer is for the new question. 13.318 years I think they really wan the interest compounded yearly.
Okay. So how about the question I posted just recently?
YES ----- >>>> 13.318
lol sorry. Let me do the work
this is compound or simple?
I got it... It was compound
can you help me with another problem plz?
Yes that is what I am trying to figure out. Enter my answer 13.3 years, see if it is correct, then I will know what they are asking for.
I can't... Lol I have to answer all 7 questions before I can submit. I only get 3 times to submit so I have to redo 6 more problems....
here is my other question... For the cash flow diagram below, which equation demonstrates the correct functional notation that will solve for the unknown Z? Z = -5000(F/P,8%,4) - 3500(F/P,8%,1) + 2000(F/P,8%,2) Z = -5000 + 2000 - 3500(F/P,8%,1) Z = -5000 + 2000(F/P,8%,2) -3500(F/P,8%,1) Z = -5000 + 2000(P/F,8%,2) - 3500(P/F,8%,3) Z = -8500(F/P,8%,4) + 2000(F/P,8%,2)
Okay much easier. What do you think?
let me stair at it more
Very good take you time.
does the interest rate account for all the money borrowed or lend?
does it account for the 5 years is what I am asking
Yes. In the real world, not many people will lend money without charging you interest.
a?
It is A, very good.
wait a min... why is some of them say P/F and F/P
should it be P/F
nvm that is notation. i need to read more about that...
??? I'm not seeing any question.
Jana just received a graduation gift of $43385 from her parents. She decides to deposit it into an account that pays a guaranteed 4% per year, compounded annually. How much will she have in the account when she retires in 28 years?
Here is my next question? Do you want me to make a new thread so I can give you a medal?
Actually I know how to solve this... we use F = P(1+i)^n
Metal is not important, but thanks for asking. This one uses the equation from before.... Future Value = Present Value ( 1 + Interest Rate ) ^ N You know everything, so calculate the future value.
F = P(1+i)^n = 43385(1+0.04)^28 = 130098.74
Your typing beat mine, good job.
Davis is saving money for a bicycle trip around the world. He would like to have $23651 saved in 5 years. To reach his goal, how much does Davis need to deposit today in an account paying 7% per year compounded annually?
Next question^^^
Your previous answer was right. This question is very similar Future Value = Present Value ( 1 + Interest Rate ) ^ N now solve for the present value.
so future value is 23651?
yes
P = 16862.84
correct
For his trip, Davis deposited $13479 into an account paying 10% per year, compounded annually. Unfortunately, he had a medical emergency at the end of year 3 and had to withdraw $2114. At the end of year 7 he received a small inheritance and deposited $3408 into his account. How much did Davis have in his account at the end of 12 years?
I think I know how to solve this one. Let me do the work on paper and attach my answer.
Yes this was is easy, but a lot more messy ...
F=13479(1+0.10)^3 = 17940.549
17940.549 - 2114 = 15826.549
Yes. Yes.
It is very good doing in parts and checking. I already have the final answer, but it seems too high to be correct. Keep going with what you are doing.
F = 15826.549(1+0.10)^2 = 19150.12439
P = 19150.12439 + 3408 = 22558.12429
F=22560.07
Wait a second let me check something
Why did you use TWO years
F = 15826.549(1+0.10)^2 = 19150.12439 Why two years? The end of year 7 from year 3, it should be FOUR years. Right?
oops....
F = 15826.549(1+0.10)^4 = 23171.65 P = 23171.65 + 3408 = 26579.65 F = 26579.65(1+0.10)^7 = 51796.22
Almost let check....
That is not the answer????
F = 26579.65(1+0.10)^7 = 51796.22 This is wrong number of years it is not 7 what should it be?
5
End of year 7, he made the deposit. How much did he have at the end of year 12? Yes 5.
F = 42806.79
Yep, that' what I got. You have got to be very careful with the YEARS. Other than that you did great.
Kreskin borrowed $1500 at an annual interest rate of 10% and paid off the loan (principal and interest), after several years with a $1997 check. How many years did it take Kreskin to repay the loan?
Okay I will keep that in mind.
You got this one....
1997 = 1500(1+0.10)^n solve for n
3 years
Yep
If a sum is worth $615 today and it will be worth $731 two years from now, how much was it worth one year ago?
(615+731)/2 = 673
673-615 = 58
I don't know but I don't think it is that simple.
You need to calculate the interest rate some how.
615 - 58 = 557
FV = PV (1+IR)^N you know everything but IR
673 for every 1 year
Once you know the IR you can find the value at end of year one.
Don't forget the first year will earn less than the second year. Compound interest is still in affect.
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