Simplify the following expression, explain your steps. (x^2+3x-4)/(x^2+5x+4)
im not sure where to start
quadratic equation so `factor`
in order to simplify you should by factoring both quadratic equations. do you know how to factor them?
no not really
well the leading coefficient of 1 so you can apply AC method find two numbers when you multiply them you should get product of AC (a=leading coefficient and c=constant) and the sum of same numbers should be equal to b (coefficient of x term) \[\rm Ax^2+Bx+C=0\] a=leading ceofficient b=coefficient of x term c=constant
x^2+3x-4 a=? b=? c=?
wouldnt that make it 3 and -2?
wait i didnt see the second part. A= 1 b= 3 and c = -4
^^ye coorrect.
so product of AC =1 times -4 =-4 so when you multiply those two numbers you should get -4 and the coefficient of x term is 3 so the sum of same two numbers should be 3
so 4 and -1
correct ans since the leading coefficient is one so you can write as (x + 1st number)(x+2nd number ) factors of x^2+3x-4
doesn't matter which number u put first it can be -1 or 4
okay that makes sense but im not sure where to go from there?
now factor the denominator
x^2+5x+4 same method find two numbers.
so 5 and -1
hmm what is the product of AC ??
|dw:1452817252409:dw|
Join our real-time social learning platform and learn together with your friends!