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Mathematics 12 Online
OpenStudy (baseballguy101):

Simplify the following expression, explain your steps. (x^2+3x-4)/(x^2+5x+4)

OpenStudy (baseballguy101):

im not sure where to start

Nnesha (nnesha):

quadratic equation so `factor`

Nnesha (nnesha):

in order to simplify you should by factoring both quadratic equations. do you know how to factor them?

OpenStudy (baseballguy101):

no not really

Nnesha (nnesha):

well the leading coefficient of 1 so you can apply AC method find two numbers when you multiply them you should get product of AC (a=leading coefficient and c=constant) and the sum of same numbers should be equal to b (coefficient of x term) \[\rm Ax^2+Bx+C=0\] a=leading ceofficient b=coefficient of x term c=constant

Nnesha (nnesha):

x^2+3x-4 a=? b=? c=?

OpenStudy (baseballguy101):

wouldnt that make it 3 and -2?

OpenStudy (baseballguy101):

wait i didnt see the second part. A= 1 b= 3 and c = -4

Nnesha (nnesha):

^^ye coorrect.

Nnesha (nnesha):

so product of AC =1 times -4 =-4 so when you multiply those two numbers you should get -4 and the coefficient of x term is 3 so the sum of same two numbers should be 3

OpenStudy (baseballguy101):

so 4 and -1

Nnesha (nnesha):

correct ans since the leading coefficient is one so you can write as (x + 1st number)(x+2nd number ) factors of x^2+3x-4

Nnesha (nnesha):

doesn't matter which number u put first it can be -1 or 4

OpenStudy (baseballguy101):

okay that makes sense but im not sure where to go from there?

Nnesha (nnesha):

now factor the denominator

Nnesha (nnesha):

x^2+5x+4 same method find two numbers.

OpenStudy (baseballguy101):

so 5 and -1

Nnesha (nnesha):

hmm what is the product of AC ??

Nnesha (nnesha):

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