Question

An object has a constant acceleration of 40 ft/sec^2, an initial velocity of -20 ft/sec, and an initial position of 10 feet. Find the position function, s(t), describing the motion of the object

Answer 1

S(t) = 40t^2 - 10t + 10

Answer 2

Sorry, -20t. Am I correct?

Answer 3

position function will be\[s(t) = s_0 + v_0t + \frac{1}{2}at^2\]where \(s_0\) is the initial position and \(v_0\) is the initial velocity and \(a\) is the acceleration.

Answer 4

not quite...

Answer 5

2 of 3 terms are correct, but one is not.

Answer 6

so S(t) = 10 - 20t + 20t^2?

Answer 7

yes, that's correct.

Answer 8

Awesome, thanks!!!!

Answer 9

position function will always have that general form, but if the initial position is 0, or the initial velocity is 0, then those terms will vanish, of course.