Question

PLEASE HELP I BEG YOU!

Answer 1

@hhelpplzzzz

Answer 2

@haleyelizabeth2017

Answer 3

well the x- value in the vertex is the line of symmetry.

so if you have a parabola

\[y = ax^2 + bx + c\]

then the line of symmetry is

\[x = \frac{-b}{2a}\]

substitute the values of a and b for each equation and you'll find one will have a negative value. That will be the answer

Answer 4

um confused because i need to chose more than one i think one is number 1

Answer 5

ok, so the 1st parabola has a = -8 and b = 4, then

\[x = \frac{-4}{2 \times -8}\]

what's the value..?

Answer 6

Oh, and I think you'll find there is only 1 solution

Answer 7

so only one asnwer that is number one!

Answer 8

???????

Answer 9

I posted what you need to do for the 1st parabola... above...

what is the value of x = (-4)/(2x-8)....?

Answer 10

x = 3 i think :/

Answer 11

are u there :(

Answer 12

if you evaluate


\[x = \frac{-4}{2 \times - 8} = \frac{-4}{-16} = \frac{1}{4}\]

so you get a positive x value.. so you can ignore option 1.

so now repeat the precess for options 2,3 and 4