Question

Solve x2 + 8x − 3 = 0 using the completing-the-square method.

Answer 1

these are the answer choices
x = four plus or minus the square root of three
x = negative four plus or minus the square root of three
x = four plus or minus the square root of nineteen
x = negative four plus or minus the square root of nineteen

Answer 2

x^2 + 8x = 3
Take the x coefficient ; divide it by 2; square it then add to both sides of the equation
8/2 = 4
4^2 = 16
x^2 + 8x +16 = 3 + 16
(X+4)^2 = 19
X+4 = sq root of 19

Answer 3

wow thank you so much wolf

Answer 4

Can you help me with two other questions?

Answer 5

I'm still seeing if I got that right (and also trying to see which multiple choice answer is correct).

Answer 6

Using the completing-the-square method, rewrite f(x) = x2 − 8x + 3 in vertex form.

f(x) = (x − 8)2
f(x) = (x − 4)2 − 13
f(x) = (x − 4)2 + 3
f(x) = (x − 4)2 + 16

Answer 7

Rewrite f(x) = –(x + 3)2 − 1 from vertex form to standard form.

f(x) = –x2 − 6x − 10
f(x) = x2 + 6x + 8
f(x) = x2 − 6x − 8
f(x) = x2 − 8

Answer 8

please help me wolf

Answer 9

not sure about vertex form - and I'm on a phone call at the moment

Answer 10

oh ok thanks for your help though

Answer 11

Using the completing-the-square method, rewrite \(f(x) = x^2 − 8x + 3 \) in vertex form.

So vertex form is just \[y = (x-h)^2 + k\]with the vertex at \((h,k)\)

Complete the square and replace \(y\) with \(f(x)\)



Rewrite \(f(x) =\ –(x + 3)^2 − 1\) from vertex form to standard form.

Even easier — just expand the right hand side of the equation.

Answer 12

thank you so much