Question

Any Help Would Be Greatly Appreciated. Thanks!

What was the ratio of Cu+2 to S-2?

I'm not entirely sure of what is being asked here, I can post more info if you think that is necessary.

Answer 1

what they are asking for is the ratio.
The compound is CuS ratio 1:1

Answer 2

So it simply is Copper Sulfide 1:1? Could you explain briefly?

Answer 3

For every 1 formula unit of Copper(I) Sulfide, there are 2 Copper ions.
For every 1 formula unit of Copper(II) Sulfide, there is 1 Copper ion.
The reason for this has to do with the charge on the Sulfide ion (which is S-2, with a -2 charge). The over all charge on the compound must be neutral , so the Copper ions and Sulfide ions combine together in the right ratio to cancel each other out.

It takes 2 Cu+1 ions to cancel out the charge of 1 S-2 ion, so they combine in a ratio of Cu+1 : S-2 = 2 : 1.
It takes 1 Cu+2 ion to cancel out the charge of 1 S-2 ion, so they combine in a ratio of Cu+2 : S-2 = 1 : 1.

Answer 4

Thank you

Answer 5

anytime