Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in standard form. 4, -14, and 5 + 8i
HI!!
first start out by writing the two easy factors it is clear that if one of the zeros is 4 then one factor is \(x-4\)?
Okay so the factors would be x-4, x+14, x-(5+8i), x- (5-8i)?
yes, and it is easy to multiply out \((x-4)(x+14)\) but it is harder to multiply out the last two there is however an easier way to find the quadratic with zeros \(5\pm 8i\)
actually there are two easy ways, one is easy, one is real real easy, but the real real easy way requires memorizing something so if you are going to to only one or two the easy way might be preferable you pick
Can we do the on that requires memorization? Itd probably help more in the long run
ok sure if a zero of a quadratic is \(a+bi\) then the quadratic is \[x^2-2ax+(a^2+b^2)\]
in your case \(a=5,b=8\)
so what do you get for \[(x-(5+8i))(x-(5-8i))\] doing it the real quick way?
X^2 -10x + 89?
Then do I multiply that with the foil of (x-4)(x+14)?
correct
(x^2 -10x + 89)(x-4)(x+14)?
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