Question

Find the general form...

Answer 1

Question 1

Answer 2

Question 2

Answer 3

Ax +By = C

Find the slope using:

\[\frac{ \Delta y }{ \Delta x } = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }\]

Plug the value in :

m : slope , b : y - intercept.

\[y = mx + b\]

use any given point, then solve for b.

Put the final answer on the form :

\[Ax + By = C\]

Answer 4

@TrojanPoem for the first one I got y=-11/15 x - 8/5 I just don't see that as a choice?

Answer 5

General form is

Ax + By = C

Multiply both sides times 15, them get x, y to a separate side.

Answer 6

ok
from the slope u obtain, -11/15
y=mx+b
we solve for b
using (-9,5)
5=(-11/15)(-9)+b
5=99/15+b
5-99/15=b
-1.6=b
equation
y=-11/15x-1.6
multiply both sides by 15 we get
15y=-11x-24
we now carry everything to one side
15y+11x+24=0

Answer 7

Thank you :)

Answer 8

for question 2
put the equation of the line given in the form y=mx+b,
by doing this u will obtain the slope of that line. then u can find its perpendicular slope
by m*m1=-1

Answer 9

the product of the two slopes must equals -1 for the two lines to be perpendicular

Answer 10

would that be 5x - 3y + k = 0

Answer 11

no not really

Answer 12

3x+5y-8=0
we want to find the slope of this line
so we put it in the form y=mx+b

first we carry over the 3x by subtracting 3x and the -8 by adding 8 we get
5y=-3x+8
we now divide throughout by 5

Answer 13

y=mx+b
with m=slope
wats the slope for the line?

Answer 14

-3/5

Answer 15

correct

Answer 16

not m*m1=-1
m=-3/5
so
(-3/5)*m1=-1

wats m1=??

Answer 17

type error not* shd be now*

Answer 18

would that be 5/3

Answer 19

sorry my battery went
and yes the new slope is
m1= 5/3

Answer 20

with this slope and the given point (-8, 1)
we find the equation of the line then put it in general form

Answer 21

y=mx+b
1=5/3(-8)+b
b=??