Question

State whether every point on the graph is a solution of the equation.

Explain why or why not.

3x – 2y = –6



A.
Every point shown on the graph is a solution of the equation because when the coordinates of the points are substituted into the equation, the equation is true for all the points.

B.
Every point shown on the graph is not a solution of the equation because when the coordinates of the points are substituted into the equation, the equation is not true for all the points.

https://static.k12.com/calms_media/media/713500_714000/713723/3/a57725e736dd7d9bc694286

Answer 1

@IvyJane @MeganXOXO @tanner23456

Answer 2

@jtug6

Answer 3

will give a medal and be a fan

Answer 4

the link doesnt opens it gives error

Answer 5

https://static.k12.com/calms_media/media/713500_714000/713723/3/a57725e736dd7d9bc694286f0b54a6f8d5d3f6c6/74652_question.jpg

Answer 6

there

Answer 7

ok

Answer 8

the points on the graph are
(-4,-2)
(-2,0)
(0,3)
(2,5)

Answer 9

Appears like B is the answer. Atleast when x = -4, 2 it doesnt appear to be true

Answer 10

ok thank you

Answer 11

can i ask you some more questions

Answer 12

Try it yourself though. Isolate the y variable using algebra then plug in -4 and 2 and see if it spits the same y-value as whats on the graph.

Answer 13

Sure why not

Answer 14

we solve for y
3x-2y=-6
3x+6=2y
3/2x+3=y

we now use each of the given points provided the x coordinate and see if we get back the corresponding y coordinate.
so (-4,-2)

3/2(-4)+3=y
-6+3=y
-3=y
so with this first proving false then every point shown on the graph is not a solution

Answer 15

Well if you try x = -2 and x = 0 it gives the correct y-value as shown on the graph, or at least for me. Maybe I might've done something wrong :p but if (-2, 0) is a point y = 3/2(-2) + 3 = 0 so that point is correct and same goes for x = 0