Question

solve algebraically:

x^2 +y^2 +2x-4y=20
3x+4y=5

Answer 1

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Answer 2

@Wendy.Ivette11714
@xXsebastianXx
@YoungStudier
@victoria_grace
@Zeronknight

Answer 3

I know the answer I just need to algebraically solve it :/

Answer 4

we complete the square on x^2+y^2+2x-4y=20
we first group the corresponding variable
so
x^2+2x+y^2-4y=20
what we do now is, take half of the 2 infront of the x and half of the -4 and then..square them... add the squared value to the right side of the equation
(x+1)^2+(y-2)^2=1+4+20

Answer 5

so from there what do i do?

Answer 6

someone help please

Answer 7

(x+1)^2+(y-2)^2=25
so
x=-1 , y=2 with r=5
since its a circle with radius 5 and center (-1,2)
are those ur answer

Answer 8

here Ill show you the file. It would be #8

Answer 9

o they are grouped equations.. taught they were separate

Answer 10

yeah they're grouped.

I thought the same at first

Answer 11

ok i had to actually work this out on paper

Answer 12

let me retake the picture clearer

Answer 13

Wow!! thank you so much!

Answer 14

y answer correct though?

Answer 15

was my*

Answer 16

yes the answers were correct ... actually those 2 points are the points of intersection where those 2 equations meet