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Mathematics 7 Online
OpenStudy (raven45):

I think I got it. Simplify the radical expression.

OpenStudy (raven45):

OpenStudy (raven45):

i chose 16

OpenStudy (calculusxy):

not really.

OpenStudy (anonymous):

Are there any options?

OpenStudy (raven45):

OpenStudy (raven45):

OpenStudy (raven45):

10 and 16

OpenStudy (anonymous):

Okay the answer isn't 16 because the square root of 16 can be simplified to?

OpenStudy (raven45):

8

OpenStudy (anonymous):

And it would not be

OpenStudy (anonymous):

So what other option has 8?

OpenStudy (raven45):

b :) thanks

OpenStudy (jtug6):

Remember that a perfect square is for example 8*8 which is 64. 64 times what equals 128? Then remember to bring the perfect square outside of the radical because it "undoes it" basically :P

OpenStudy (anonymous):

Yes 8 √ 2 is the answer but you do understand why right?

OpenStudy (raven45):

kinda im getting there

OpenStudy (anonymous):

Like jtug said you start off with 128 right? Than what I do is divided 128 by 2 and you get 64. 8x8 is 64 :) So thats why you get 8√ 2

OpenStudy (raven45):

you made it so clear i get it now

OpenStudy (anonymous):

Your welcome :) and I gave Jtug a medal cause he helped!

OpenStudy (jtug6):

Thank you! same to you

OpenStudy (raven45):

wait so do I always divided by 2?

OpenStudy (raven45):

I have one with 500 and I divided it by 2 and got 250 so what do I do now?

OpenStudy (jtug6):

Well it depends. You have to basically try to take it apart piece by piece until you can get a perfect square. If you end with more than 1 perfect square, multiply them because interestingly enough it becomes just a bigger perfect square. Then you can find out which number times that same number equals that "bigger perfect square"

OpenStudy (anonymous):

Yeah like Jtug said i usually do just because its a start to simplifying, but than you have to find a perfect square root so it all depends on what the problem is

OpenStudy (jtug6):

Ok, so 500 for example. You divided by 2 and it gave you 250. Do it again you have 125 * 2 * 2 right? Well, 2*2 = 4 which is a perfect square. Now we have 4 * 125. So now we already have 1 perfect square BUT we still have to take apart 125. What common factor can go into 125, 5 times?

OpenStudy (jtug6):

Because 125 is only divisible by 5 or 1 fyi

OpenStudy (raven45):

25

OpenStudy (jtug6):

Yes! So, now we have 4 * 25 * 5 which still equals 500.

OpenStudy (jtug6):

Out of those three, which are perfect squares?

OpenStudy (raven45):

4 and 5?

OpenStudy (jtug6):

Not quite. 4 is correct but why couldnt it be perhaps the 25? what times what = 25?

OpenStudy (raven45):

5&5

OpenStudy (anonymous):

Okay Jtug looks like you got this one good job :) Raven if you need me just tag me :D Bye

OpenStudy (jtug6):

Thanks! Sorry I kinda took this one over. I'll let you have the rest for awhile XD

OpenStudy (jtug6):

And yes! It's 5*5 = 25 so that must mean 25 is the perfect square. Perfect squares are only made when its a whole number times a whole number just so you know. 5 can only be made when its like, 2.23 * 2.23 which clearly aren't whole numbers

OpenStudy (jtug6):

So, 4 and 25 are perfect squares? What did I mention about having more than 1 perfect square?

OpenStudy (raven45):

divide?

OpenStudy (jtug6):

Mmmmm opposite of it. Because if you multiply them it becomes one giant perfect square. So what is 25*4? And then what do you do with that value since its underneath the radical?

OpenStudy (raven45):

90 and muliply

OpenStudy (jtug6):

Check your math again. What's 25 times 4?

OpenStudy (raven45):

100

OpenStudy (jtug6):

Aha. And now we have a bigger perfect square. So now we have 100*5 which still equals 500. So now what do you do with the 100 since it's a perfect square and underneath the radical?

OpenStudy (raven45):

IM not for sure

OpenStudy (jtug6):

Okay, well, if you'd like to think of it like this the square root (underneath radical) of 100 is 10, because 10 times 10 is 100. Alternatively with 25*4*5 we can say the square root of 25 and 4 is 5 and 2 which we then multiply to give us the same value, 10. So what do we do with 10 if we know that the remainder in the square root is 5?

OpenStudy (raven45):

OpenStudy (jtug6):

Yes!!!

OpenStudy (raven45):

ohh thanks

OpenStudy (raven45):

i have another one

OpenStudy (jtug6):

and heres a simple way to put it back together. We can take the 10 from the outside and multiply it by itsself to get 10*10 = 100 right? Now we put the 100 in the radical and multiply it by 5, which gives us the original square root of 500.

OpenStudy (raven45):

Simplify the expression.

OpenStudy (raven45):

@GoodVibess

OpenStudy (jtug6):

Ah. Remember what is common? Also that it's addition so what do we do with 6 and 5 again?

OpenStudy (anonymous):

Oh hi sorry I was on a different question

OpenStudy (raven45):

the 6 and multiply it?

OpenStudy (jtug6):

Not quite it's addition and the radicals are common so we ____?

OpenStudy (anonymous):

\[500=2^2 5^3 \] from Mathematica's FactorInteger function.

OpenStudy (anonymous):

Sorry Raven I forgot how to divide Square Roots :/

OpenStudy (raven45):

add

OpenStudy (jtug6):

Yes! So 6+5= 11 and the 6 doesnt contain a perfect square so it stays the same. So what does it look like altogether?

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