can someone help me with this problem Which system of equations is represented by the graph? y = x2 − 6x − 7 x − y = 1 y = x2 − 6x + 7 x + y = −1 y = x2 + 6x − 7 x − y = 1 y = x2 + 6x + 7 x + y = 1
i dont know
do you know
not a clue
ask a proffesional what grade is this
junior in high school
dang i am a freshman in high school
algebra 2 to be exact
why are you doing work on a saturday
so i get it done
homework?
then have the whole 3 day weekend off
i have to go to a stupid saturday school
why
i was absent for 6 days without bringing a note
i am on here asking questions to a worksheet that we are doing
oh my school has had two threats in the past 2 days one a bomb and one a gun
:o
what state is your school in
yeah sketchy
alright see ya
Which system of equations is represented by the graph? y = x2 − 6x − 7 x − y = 1 y = x2 − 6x + 7 x + y = −1 y = x2 + 6x − 7 x − y = 1 y = x2 + 6x + 7 x + y = 1 Look at the line on the graph first. What is the slope of the line? What is the y-intercept?
slope and y are 5?
Let's start again.... Where does the line cross the Y axis?
at 1
can you tell me if the second one is the answer because thats what i got
Yes. The y-intercept is where the line crosses the y axis. So it is the variable b in the y-intercept form for the equation of a line. y = mx + b so right now we have y = mx + 1 the m variable is use to represent the slope What is the slope (m) of the line? m = (y2 - y1) / (x2 - x1) The graph has labelled two points on the line that intersect the parabola. Use the equation m = (y2 - y1) / (x2 - x1) to determine the slope of the line
so it would be the second one
yes
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Hint: It is not the second one, as the second on indicates an intercept of -1 and the graph indicates a positive 1.
You have at least two choices here: You could work backwards from the graphs to the equations, or you could graph each of the four sets of 2 equations and compare your graph to the given graph. Your choice!
Sorry, I thought he meant the second slope equation I wrote, even though they were both the same. Thanks for jumping in.
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