Question

Use the value of the trigonometric function to evaluate the indicated functions such as given cos(t) = 3/5.
1) cos( pi - t)
2) cos ( t + pi)

Answer 1

so cos (t) = -(-3/5)

Answer 2

how do you apply the odd even formulas to the problem?

Answer 3

cosine and secant are even but i'm not understanding how the answer changes to equal negative 3/5 form positive 3/5

Answer 4

or u can open cos (A+B)=cos A cos B -sin A sin B
and cos (A-B)=cos A cos B + sin A sin B

Answer 5

I'm confused how odd and even functions work solving this problem

Answer 6

what are even and odd function,tell me thhen i expalin u.

Answer 7

says given sin t = 4/5 then problem sin(pi-t) = 4/5 and sin(t+ pi) = -4/5 ...sin is an odd function

Answer 8

sorry

Answer 9

i write formule for pi/2

Answer 10

cos and sec are the only even trig functions

Answer 11

cos (pi-x)=-cos x
cos (pi+x)=-cos x

Answer 12

can you explain how that equals -cos x

Answer 13

is this because cos is the x value which never changes?

Answer 14

since (pi-x) is in II Quradent and in II cos is -ve and (pi+x) is in III and cos is -ve in III cos is +ve only in I and IV quradent.

Answer 15

so knowing the formula how can i write one of those two problems
would this be correct
cos(pi - x) = cos(pi -(3/5)) = cos(pi) -cos(3/5) so cos = -3/5

Answer 16

No cos (pi-x)=-cos x=-3/5

Answer 17

so cos(x+pi) = -cos x = -3/5

Answer 18

understand or not

Answer 19

not really.. im looking at an easier problem Given: sin(-t) = 4/7
So this can be stated as sin(-t) = - sin(t) = -(-4/7) .... why is this not -4/7

Answer 20

if sin(-x)=a then -sin x=a or sin x=-a

Answer 21

so if cos x = -3/4 given
cos(-t) = -3/4
sec(-t) = -4/3

Answer 22

I think your best bet is to use the difference formula for the cosine function to answer this question. cos (a-b) = cos a cos b + sin a sin b.

Please evaluate cos (pi - t). Think carefully: what is the value of cos pi?