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Mathematics 7 Online
OpenStudy (mathmath333):

find the length of arc AB

OpenStudy (mathmath333):

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OpenStudy (anonymous):

You wanna solve it in radians or degrees?

OpenStudy (mathmath333):

what do u mean

OpenStudy (anonymous):

Well do you know what radians are and how to use them?

OpenStudy (mathmath333):

i know cm , m , km and 1 radian =pi/180

OpenStudy (anonymous):

Well then \[\large \sf Arc=r\theta\] Just use theta in radians

OpenStudy (mathmath333):

but i have read a formula that arc=2*pi*r*\theta /(360)

OpenStudy (anonymous):

That is if you have theta in degrees. That is why I asked at the beginning, so I would know what formula to give you. Radians is easier, but both are valid and it is your preference in which one to use

OpenStudy (mathmath333):

\(\Large \sf Arc=\dfrac{2\pi r\times \theta^{\circ} }{360^{\circ}}\)

OpenStudy (mathmath333):

which one is correct if it is not given abt radians

OpenStudy (anonymous):

\[\large \sf 5\frac{\pi}{3} = \frac{2}{6} \pi 5\] They are both correct

OpenStudy (anonymous):

You can use either formula and you will get the same answer, just use the theta as 60 degrees or pi/3 radians

OpenStudy (mathmath333):

thank

OpenStudy (anonymous):

ye no prob

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