Question

In △JKL, solve for x.

Triangle JKL where angle K is a right angle. KL measures 34. JL measures x. Angle J measures 27 degrees.

66.73
74.89
15.44
38.16

Answer 1

it's tan cos and sin. Just identify the appropriate sides and solve! Tell me if you need more detailed explanation :D

Answer 2

yes pleases

Answer 3

ok I'm just gonna assume you know the basics of tan, cos and sin.
you know that KL is 34. So you need to use one of these 3 (tan cos and sin) which involves both the x side and KL side.
Your reference angle is Angle JKL which is 27˚.From this reference point, X is the hypotenuse and 34 is the opposite side. So which one (tan cos or sin) uses both hypotenuse and opposite side? Tan.
So you basically get Tan 27˚=34/x
From there calculate and you'll get x
Hope this helps

Answer 4

ok, thank you I will calculate and tell you my asnwer to make sure it's correct

Answer 5

Is it 74.89?

Answer 6

no... wait let me recalculate. Maybe it's me who's wrong

Answer 7

OH MY IM SO SORRY. I used the wrong one. It shouldn't be tan. It should be sin

Answer 8

yes you are right (sorry about that)

Answer 9

sin J =LK/KJ
sin 27=34/x
x=34/sin 27

Answer 10

weird that I got it right.. I must have used the right one

Answer 11

oh ok thank you @Er.Mohd.AMIR