One pipe fills a pool in 4 hours. A second pipe, used to drain the water from the pool, can empty the pool in 8 hours. The owner of the pool mistakenly opened both pipes. How long will it take to fill the pool if one pipe is filling and the other is emptying?
Hi!!
Hi!
one has rate \(\frac{1}{4}\) the other has rate \(-\frac{1}{8}\) the combined rate is what you get when you ... combine them what is \[\frac{1}{4}-\frac{1}{8}\]?
\(\large \frac{2}{8} - \frac{1}{8} = \frac{1}{8}\)
ok so the this system of silliness fills one eighths of the pool per hour
how many hours to fill the whole pool?
i don't understand but i guess \(\large \frac{1}{8}\)?
oh no
it fills only one eighths of the pool per hour
so how many hours for the entire pool to be filled?
okay so do we divide \(\large 1 \div \frac{1}{8}\) ?
you can, or i would just think one eighths per hour, 8 hours for the whole pool
your thinking seems more logical. thank you!
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