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find the domain of f(x)= √(ln(x-2))
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log (x-2 ) must be grater then zero so x is
HI!!
actually you need to solve \[\ln(x-2)\geq 0\]
do you know how to do that?
no
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log 1=0
so x=2 is one solution?
\((x-2)> 0\)
In fact, f(x)=lnx ln(x)≥0 --> e^ln(x)≥e^0 --> x≥1 whereas the correct domain is x>0
log 0 is not define so x-2 is greater then zero not equal to.
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yes, i corrected that.
hmmm
this is not correct
\[\ln(x-2)\geq 0\] is the first step
then put in equivalent exponential form as \[x-2\geq e^0\]
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since \(e^0=1\) we now have \[x-2\geq 1 \] solve that in one step
thank you
I apologize, didn't see the √ :)
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