Mathematics
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OpenStudy (anonymous):
will medal and fan for help (so help please)
find the 50th term of the sequence 5, -2, -9, -16, ...
A. -352
B. -343
C. -338
D. -331
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OpenStudy (er.mohd.amir):
here common diff d=-2-5=-7 and a=5
n th term=a+(n-1)d
OpenStudy (er.mohd.amir):
where n is number of term a is first term and d is common difference
OpenStudy (anonymous):
so it would be a(50)=5+(50-1)*-7
OpenStudy (anonymous):
right
OpenStudy (er.mohd.amir):
yes
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OpenStudy (anonymous):
which would turn into a(50)=55-1*-7
which would than be a(50)=54*-7
which would produce a(50)=-378
OpenStudy (anonymous):
correct
OpenStudy (er.mohd.amir):
5+(50-1)*-7
=5-7*49
OpenStudy (anonymous):
and then it would be5-343
which would then be -348
OpenStudy (anonymous):
right
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OpenStudy (er.mohd.amir):
5-343=-338
OpenStudy (anonymous):
so it would be C. correct
OpenStudy (er.mohd.amir):
yes
OpenStudy (anonymous):
what about another question
OpenStudy (er.mohd.amir):
which one
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OpenStudy (anonymous):
find the arithmetic mean of an of a\[a _{n-1}=3.9\] and \[a _{n+1}=7.1\]
OpenStudy (er.mohd.amir):
put 3.9=a+(n-1-1)d
and 7.1=a+(n+a-1)d and solve then get a and d
OpenStudy (anonymous):
so it would be 1.7
OpenStudy (anonymous):
i mean 1.6
OpenStudy (er.mohd.amir):
3.9=a+(n-1-1)d
7.1=a+(n+1-1)d
subtract it
7.1-3.9=a+nd-a-nd+2d
3.2=2d
d=1.6
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OpenStudy (anonymous):
so i was right
OpenStudy (er.mohd.amir):
now solve a
OpenStudy (anonymous):
3.6
OpenStudy (er.mohd.amir):
u try to find AM so u can simple add and divide by total numbers of terms
OpenStudy (anonymous):
so i am right