Can a linear function be continuous but not have a domain and range of all real numbers?
HI!!
sure why not?
first of all, the domain of a function is something the creator of the function controls, so you can say the domain is anything you like this is not the answer they are looking for however
the answer they are looking for is an example of a linear function whose domain is \(\mathbb{R}\) but whose range is not hint, what linear function has only one range element?
idk im confused cuz i just started this topic
a linear function looks like \[f(x)=mx+b\]a line with slope \(m\) and \(y\)-intercept \(b\)
i wrote that its yes because as long as the domain doesnt repeat it can be anything
if \(m=0\) then you get \(f(x)=b\) a constant function the domain is still all real numbers, but the range is only one number the line is horizontal
but doesnt it say that the domain and range cant be real numbers?
@misty1212
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