I need help with Algebra 2A IM ABOUT TO FAIL THIS CLASSSSS!!!!!!!!
i just need someone to walk me through this
when is it due because i am Algebra 2a right now
it's been due im just behind
let me see because i never did anyprojects in my class just test
uh i get help tyou with the last part
uh which part is confusing you
all of it
ok so for the last part i will give you examples|dw:1453084137774:dw|
what is that
roots tutorial.math.lamar.edu/Classes/Alg/ZeroesOfPolynomials.aspx
you should know what vertex is
Let's talk about the PDF question.
you are given 3 coordinates
and what you basically need is a formula
the quadratic equation is in the form ax^2 + bx + c
i dont know how to set it up
well every x coordinate we plug into the equation we should get the corresponding y
vertex is usully 0,0 i would help but these are resources i use and if i help toom much i would confuse me because we worked on zeroes not roots just use your scientific caculator and liik online.
or graphing caculator
yes i have it up
or online graphing caculaator
thus for (2.6, 7.9): f(2.6) = a(2.6)^2 + 2.6b + c = 7.9
now you tell me the equation for the next 2 coords
f(4.8)=a(4.8)^2+4.8b+c=12.4 f(9.7)=a(9.7)^2+9.7b+c=15.1
yes very well done... now what should we do with these 3 equations to find a,b and c
i dont know walk me through
It looks like a system of equations right. You have all the information you need
do you know how to solve 3 equations, 3 unknowns?
no
How about 2 equations, 2 unknowns?
no
oh.. okay.. let's start with something simpler.. y=2x-1 y=4x+3
we have 2 strategies: 1. Elimination 2. Substitution
we can use both, however one is always easier than the other. depends on the equation
Substitution
yes.. since y is equal to 2x-1 and 4x+3, we can set them equal to each other
solve for x and then plug x back in to any of the two equations to find y
2x-1 = 4x+3 solving for x, we get -2
y=−5, x=−2
yes very well. in elimination we try and cancel one term by adding or subtraction
thus these two terms must have equal coeficcients
positive or negative does not matter. same magnitude
we 2x-1=y -) 4x+3=y -------------------- -2x-4=0 x=-2
ta da.! now in 3 equation 3 unknown, we use the same strategy: EQUATION 1 EQUATION 2 EQUATION 3 1. EQUATION 1 +/- EQUATION 2 = EQUATION A 2. EQUATION 1 +/- EQUATION 3 = EQUATION B 3. EQUATION A +/- EQUATION B = a answer for 1 of the variables
do you think you can apply this to the question?
can you teach how to set it up
a(4.8)^2+4.8b+c=12.4 a(9.7)^2+9.7b+c=15.1 a(2.6)^2 + 2.6b + c = 7.9
try using elimination method, it will be easier in computation
Join our real-time social learning platform and learn together with your friends!