Question

tan(pi/5) - tan(pi/30) / 1 + tan(4/5)tan(pi/30)

Answer 1

@perl

Answer 2

Somebody help

Answer 3

$$\large \frac{\tan(\pi/5) - \tan(\pi/30)}{ 1 + \tan(\pi/5) \cdot \tan(\pi/30)} =
\tan ( \pi / 5 - \pi /30 ) = ~?
$$

Answer 4

Hold on ima plug it into my calculator

Answer 5

you dont need calculator, since you want an 'exact answer'
unless your calculator is capable of doing this

Answer 6

$$\large \frac{\tan(\pi/5) - \tan(\pi/30)}{ 1 + \tan(\pi/5) \cdot \tan(\pi/30)} =
\tan ( \pi / 5 - \pi /30 ) = \tan( \pi / 6 ) $$

Answer 7

Awww...I wanted to solve it myself...

Answer 8

But how did you get that end result like that 6

Answer 9

U divided 30 by 5??

Answer 10

$$ \large \frac{\pi }{5} - \frac{\pi}{30} =
\color{red}{\frac{6}{6}}\cdot \frac{\pi }{5} - \frac{\pi}{30}=
\frac{ 6\pi }{30} - \frac{\pi }{30} = \frac{5\pi }{30} = \frac{\pi }{6}$$

Answer 11

yes thats correct

Answer 12

divide top and bottom by 5

Answer 13

Ohhhh ok i get it

Answer 14

I have another question tho...Im srry

Answer 15

so whats tan (pi/6) ?

Answer 16

5pi/30 or pi/5 - pi/30

Answer 17

Is that what ur asking??

Answer 18

tan pi/6 can be evaluated as a number , a radical

Answer 19

just like before tan (45) = 1,
tan(pi/6) = ?

Answer 20

sqtroot2(3) ?

Answer 21

tan (pi/6) = sin(pi/6) / cos(pi/6) = ( 1/2 ) / ( sqrt(3) / 2) = 1 / sqrt(3)

Answer 22

I feel dumb

Answer 23

$$ \large \tan (\pi/6) = \frac{\sin(\pi/6)}{ \cos(\pi/6)} = \frac{ 1/2 }{ \sqrt{3} / 2} = \frac{1}{\sqrt 3} = \frac{\sqrt 3 }{3} $$

Answer 24

so the final answer is sqrtroot(3)/3?

Answer 25

yes, with rational denominator

Answer 26

Wanna help again or its past curfew??

Answer 27

sure you can post a new question. if I am around i will look at it.

Answer 28

k