Question

36-4(2)(8) what is the real and complex roots? PLEASE HELP i will medal!!!!

Answer 1

This looks like a simple algebraic expression involving subtraction and multiplication.

What roots?...

Answer 2

Oh oh oh, ok ok I see what this is :) lol

Answer 3

So this is the value of your `discriminant`.

Answer 4

ok

Answer 5

You're dealing with something like this:\[\large\rm \sqrt{36-4(2)(8)}\]And they want you to just look at this part of it,\[\large\rm 36-4(2)(8)\]If it's negative, then you have a negative number under the square root,
which corresponds to an imaginary number (complex roots)

Answer 6

So do the algebra real quick,
multiply, then subtract.

Do you get negative, positive, or zero as an answer?

Answer 7

i get -28

Answer 8

Ok good :)
Negative number:
So when you take the root of negative,\[\large\rm \sqrt{-28}=i \sqrt{28}\]it gives an imaginary number.

So we would have `zero real roots`,
and `two complex roots` because complex roots always come in pairs of two.
And this is a `quadratic`, which has only two roots.

Answer 9

okay that makes alot more sense! thank you!!!

Answer 10

np