i think the answer is 121? not sure how to answer this will post screenshot
121? hehe that seems way too large :D
So like..
\[\large\rm y=x^2+bx\]To complete the square, Toby adds 121 to each side,\[\large\rm y+121=x^2+bx+121\]
121 is a perfect square, do you know which one? :) Hint 12*12 = 144 9*9 = 81 it's somewhere between there, ya?
9?
so thats the coefficent?
oh you mean for 121!!
9*9=81, not 121 0_o
wait so 9 or11?
We're not to the answer yet... I'm just asking if you can tell me the square root of 121.
oh okay that is 11
Ok good :) Let's rewrite the 121 as 11*11 then.\[\large\rm y+121=x^2+bx+11\cdot11\] When completing the square, we have this squared number on the end, and we have TWO of these x's in the middle. So the completed square should look like this:\[\large\rm x^2+11x+11x+11\cdot11\]
So what is the coefficient on your x term? :) Combine like-terms first!!
Or if this easier for you, square root the 121, then double that number. That's how you find the middle coefficient ^^
x^2+22x+121
okay so then the coefficent is 22 then
Yes :) Good job!
cool thanks
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