Mathematics
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OpenStudy (anonymous):
If θ is between 0° and 90° and tanθ = 8/7, find cosθ
A. 8√(113)
B. 7√(113)/113
C. √(113)/7
D. 8√(113)/113
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OpenStudy (anonymous):
SO i find it helpful to draw it out
OpenStudy (anonymous):
|dw:1453147129646:dw|
OpenStudy (anonymous):
Thats supposed to be theta
Do you understand why the two legs are 8 and 7?
OpenStudy (anonymous):
Because that is tantheta
OpenStudy (anonymous):
Yes so you how can you find the hypotenuse of the triangle?
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OpenStudy (anonymous):
Opposite adjacent something
OpenStudy (anonymous):
Umm try something simpler like pythagorean theorem to find the hypotnuse
OpenStudy (anonymous):
so do 8^2+7^2=c^2
OpenStudy (anonymous):
so c^2 = 15^2
OpenStudy (anonymous):
no you can't do that because you have to do the exponents first
So do (8^2) THEN add (7^2)
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OpenStudy (anonymous):
c^2 = 113?
OpenStudy (anonymous):
Yes now to get only c, you would take the square root and it would be sqrt(113)
OpenStudy (anonymous):
So now you would have
|dw:1453148090464:dw|
OpenStudy (anonymous):
AS the third side
OpenStudy (anonymous):
so what is the formula for cos?
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OpenStudy (anonymous):
The formula for cos is c2 = a2 + b2?
OpenStudy (anonymous):
Umm no, cosine is adjacent/hypotenuse right?
SohCahToa, ring a bell?
OpenStudy (anonymous):
yes yes correct
OpenStudy (anonymous):
Right so now what is cosine of theta?
OpenStudy (anonymous):
According to the picture
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OpenStudy (anonymous):
7/ √(113) ?
OpenStudy (anonymous):
Yup there you go :)
OpenStudy (anonymous):
So I guess my answer is B. then?
OpenStudy (anonymous):
Yes because that is what you get when you rationalize it
OpenStudy (anonymous):
Thank you good sir!
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OpenStudy (anonymous):
No problem