Mathematics
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OpenStudy (caroline1218):
Solve the system of equations.
13i + 5 = c
6.50i + 20 = c
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OpenStudy (caroline1218):
@jhonyy9 @imqwerty @nincompoop @mathmale
OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
set them equal and solve
OpenStudy (caroline1218):
Hey! Would you mind helping me solve this problem?
OpenStudy (misty1212):
\[\huge 3i+5=6.5i+20\] solve for \(i\)
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OpenStudy (caroline1218):
Which method are you using?
OpenStudy (misty1212):
a) subtract \(3i\) from both sides first
OpenStudy (misty1212):
b) then subtract \(20\) from both sides
OpenStudy (caroline1218):
Wait, 3i or 13i?
OpenStudy (misty1212):
oh i mis copied it is \[\huge 13i+5=6.5i+20\]
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OpenStudy (misty1212):
in that case, subtract \(6.5i\) from both sides first
OpenStudy (misty1212):
then subtract 5 from both sides, and finally divide both sides by \(6.5\)
OpenStudy (caroline1218):
@misty1212 Which method of solving a system of equations is this?
OpenStudy (misty1212):
i am not sure what you are asking
OpenStudy (caroline1218):
As in elimination, substitution, graphing
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OpenStudy (misty1212):
you have \(c=\) something and also \(c=\) something else
set those two somethings equal and solve
OpenStudy (caroline1218):
Do I have to change the equations in order to use one of those methods?
OpenStudy (misty1212):
i guess we can call it "substitution" since you are substituting an expression for \(c\) in the equations
OpenStudy (misty1212):
no, just set them equal and solve
OpenStudy (caroline1218):
Ok, so then you would consider it substitution? @misty1212
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OpenStudy (misty1212):
sure
OpenStudy (caroline1218):
Ok, thanks!
OpenStudy (misty1212):
\[\color\magenta\heartsuit\]