Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (caroline1218):

Solve the system of equations. 13i + 5 = c 6.50i + 20 = c

OpenStudy (caroline1218):

@jhonyy9 @imqwerty @nincompoop @mathmale

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

set them equal and solve

OpenStudy (caroline1218):

Hey! Would you mind helping me solve this problem?

OpenStudy (misty1212):

\[\huge 3i+5=6.5i+20\] solve for \(i\)

OpenStudy (caroline1218):

Which method are you using?

OpenStudy (misty1212):

a) subtract \(3i\) from both sides first

OpenStudy (misty1212):

b) then subtract \(20\) from both sides

OpenStudy (caroline1218):

Wait, 3i or 13i?

OpenStudy (misty1212):

oh i mis copied it is \[\huge 13i+5=6.5i+20\]

OpenStudy (misty1212):

in that case, subtract \(6.5i\) from both sides first

OpenStudy (misty1212):

then subtract 5 from both sides, and finally divide both sides by \(6.5\)

OpenStudy (caroline1218):

@misty1212 Which method of solving a system of equations is this?

OpenStudy (misty1212):

i am not sure what you are asking

OpenStudy (caroline1218):

As in elimination, substitution, graphing

OpenStudy (misty1212):

you have \(c=\) something and also \(c=\) something else set those two somethings equal and solve

OpenStudy (caroline1218):

Do I have to change the equations in order to use one of those methods?

OpenStudy (misty1212):

i guess we can call it "substitution" since you are substituting an expression for \(c\) in the equations

OpenStudy (misty1212):

no, just set them equal and solve

OpenStudy (caroline1218):

Ok, so then you would consider it substitution? @misty1212

OpenStudy (misty1212):

sure

OpenStudy (caroline1218):

Ok, thanks!

OpenStudy (misty1212):

\[\color\magenta\heartsuit\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!