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Help with calculus for a medal?...(posting below)
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\[\int\limits(5x \sqrt[3]{1-x^2}) dx\] I need help solving this...
I've done several questions like it, but I can't seem to figure out how to solve this one in particular. This is what I have so far... \[5\int\limits (x \sqrt[3]{1-x^2})\] u = 1-x^2 du = -2x Now what?
HI!!
hello
rewrite it as \[-\frac{5}{2}\int\sqrt[3]{u}du\]
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then use the power rule backwards
Oh thank you. I kept making the fraction on the outside -1/10 to get rid of both the 5 and the 2.
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