factor. 2p^3 + 6p^2 + 3p + 9
Factor by grouping. Factor out a common factor out of the first two terms. Factor out a common factor out of the last two terms. 'What do you get?
Solve each quadratic equation. Show your work. 14. (2x – 1)(x + 7) = 0 15. x + 3x = 10
i solved it on my own. can you help with these though?
In 14. the polynomial is already factored and set equal to zero. Just set each factor equal to zero and solve.
im confused
14. (2x – 1)(x + 7) = 0 2x - 1 = 0 or x + 7 = 0 Solve each equation above.
what
In 14., a product can only equal zero if one of its factors is zero. You are given the product of two factors (2x - 1) and (x + 7) is equal to zero.
The only way a product can equal zero is if at least one of the factors is equal to zero.
so thats the answer?
(2x – 1)(x + 7) = 0 Set 2x - 1 = 0 and set x + 7 = 0 Now solve each equation above.
Can you solve 2x - 1 = 0 ?
add 1 to both sides and divide by 2?
Yes. Then solve x + 7 = 0
-2?
The solution is the two answers you got separated by the word "or".
-7
2x - 1 = 0 2x = 1 x = 1/2 x + 7 = 0 x = -7 Solution: x = 1/2 or x = -7
thankyou. number 15?
In 15. is the first x supposed to be x^2, or is it correct the way you have it?
You wrote: 15. x + 3x = 10
its x^2+3x=10
Ok. The first step is to subtract 10 from both sides to have all terms on the left side equaling zero.
but the 10 is separate already
Yes, but you don't want it separate. You need it on the left side as -10. You need just zero on the right side.
x^2+3x-10=0??
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