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Chemistry 16 Online
OpenStudy (ibrafacts):

Does anyone know how to do this

OpenStudy (ibrafacts):

Question

OpenStudy (ibrafacts):

How would u set this problem up?

OpenStudy (ibrafacts):

@Frostbite

OpenStudy (ibrafacts):

@Photon336

OpenStudy (ibrafacts):

@Photon336 can u helpe me?

OpenStudy (photon336):

yeah sure

OpenStudy (ibrafacts):

thx I juts don't know how to set it up

OpenStudy (ibrafacts):

Do u know how to set it up?

OpenStudy (photon336):

Yeah, so whenever we want to figure out the number of moles we set it up like this, \[5,653 (grams)*(\frac{ mol Aluminum Acetate }{ 204.11 grams }) = 27.696 (moles) Aluminum Acetate\]

OpenStudy (photon336):

This is how you set it up, so remember this is dimensional analysis

OpenStudy (ibrafacts):

how did u get 204.11?

OpenStudy (photon336):

so remember you need to find the molar mass of aluminum acetate right? so you would either A look that number up on line or you can calculate the mass of each atom in the formula. so the molar mass is 204.1 g/mol

OpenStudy (ibrafacts):

oh

OpenStudy (ibrafacts):

@Photon336 how would u solve the first one grams

OpenStudy (ibrafacts):

|dw:1453182754011:dw|

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