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OpenStudy (ibrafacts):
Question
OpenStudy (ibrafacts):
How would u set this problem up?
OpenStudy (ibrafacts):
@Frostbite
OpenStudy (ibrafacts):
@Photon336
OpenStudy (ibrafacts):
@Photon336 can u helpe me?
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OpenStudy (photon336):
yeah sure
OpenStudy (ibrafacts):
thx I juts don't know how to set it up
OpenStudy (ibrafacts):
Do u know how to set it up?
OpenStudy (photon336):
Yeah, so whenever we want to figure out the number of moles we set it up like this,
\[5,653 (grams)*(\frac{ mol Aluminum Acetate }{ 204.11 grams }) = 27.696 (moles) Aluminum Acetate\]
OpenStudy (photon336):
This is how you set it up, so remember this is dimensional analysis
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OpenStudy (ibrafacts):
how did u get 204.11?
OpenStudy (photon336):
so remember you need to find the molar mass of aluminum acetate right? so you would either A look that number up on line or you can calculate the mass of each atom in the formula. so the molar mass is 204.1 g/mol