Use the quadratic formula to solve. If needed , round to the nearest hundredth x^2 +3=-4x
Hi there :) Welcome to openstudy! Put the equation into standered form first \[\huge~\rm~\bf~ax^2+bx+c=0\]
How would we make x^2 +3=-4x equal to 0 ? Any ideas?
let me try ... ummm \[x^2+3x+0+-4x?\]
wow that awnser looks so dumb :( sorry..
Nope not quite....and we are all here to learn no worries :D x^2 +3=-4x Add 4x to both sides what do we get?
\[4x+x^2+3=0\]
right?
Almost! :) You have it just in the wrong order. \[\huge~\rm~\bf~x^2+4x+3=0 \] \[\huge~\rm~\bf~ax^2+bx+c=0\] What are the abc values? a=? b=? c=? Hint: Use the standered form to help you figure it out :)
im drawling a blank right now
do u mind if i add you onto a website that its a white board where you can show me?? sorry im more visual ..
\(\bbox[8pt, #99ff99,border:1px solid black]{\Large \Large{x=~} \huge{ \frac{-\color{magenta}{b} \pm\sqrt{ \color{magenta}{b} ^2-4 \color{blue}{a} \color{red}{c}}}{2 \color{blue}{a}} } ~ }\) when the equation is \(\Large\color{black}{ \color{blue}{a} x^2+ \color{magenta}{b}x+ \color{red}{c}=0 }\). \(\Large\color{black}{ \color{blue}{1} x^2+ \color{magenta}{4}x+ \color{red}{3}=0 }\).
okay so then ...you have to sub the 3?
im sorry im homeschooled and my teacher doesnt do live lessons to show us how to do anything
I see. \(\bbox[8pt, #99ff99,border:1px solid black]{\Large \Large{x=~} \huge{ \frac{-\color{magenta}{4} \pm\sqrt{ \color{magenta}{4} ^2-4 \color{blue}{(1)} \color{red}{(3)}}}{2 \color{blue}{(1)}} } ~ }\) when the equation is \(\Large\color{black}{ \color{blue}{a} x^2+ \color{magenta}{b}x+ \color{red}{c}=0 }\). \(\Large\color{black}{ \color{blue}{1} x^2+ \color{magenta}{4}x+ \color{red}{3}=0 }\).
^it's all color coordianted
Solve what's in the square root first \[\huge~\rm~\bf~4^2 -4(1)(3)\] DO NOT SQUARE ROOT THIS
-4 x 1 = 4 -4 x 3 = -12
come onto the link you sent me :)
ok
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