"Since the Happy MealTM-sized nugget box (4 to a box) can now be purchased separately, the modern McNugget numbers are linear combinations of 4, 6, 9, and 20." - http://mathworld.wolfram.com/McNuggetNumber.html
yeah and I would like the Big Mac sauce with my McNuggets Please.
only addition is allowed right ?
The linear combinations of 9 and 20 actually generate all the integers
\[9x + 20y =n\] has infinitely many "integer" solutions for every integer \(n\)
But since negative McNuggets make no sense, I think subtraction should not be allowed in the linear combs
Yeah, I think you can't order negative McNuggets haha, this whole thing is making me giggle but it is interesting in and of itself haha. I think I've heard of these before a long time ago.
\[6x+9y+20z=n\] over nonegative integers
That is quite peculiar to me how you can sort of partially factor it inside as either: \[3(2x+3y)+20z = 2(3x+10z)+9y\]
Yeah this is analogous to the coin problem : \[5n+10d+25q = n\] number of cents \(n\) that can be made using nickels, dimes, and quarters
this coin problem is easy to solve : since \(\gcd(5,10,25)=5\), \(n\) must be a multiple of \(5\). So, we can make only multiples of 5 using nickels, dimes, and quarters... not very interesting..
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