A reaction having time-independent stoichiometry follows the equation
A + 2B → 2Z
Suppose that initially there are present 0.28 moles if A, 0.39 moles of B and 0.13 moles
of Z.
After a certain amount of time, 0.18 moles of A remain. What amounts of B and
Z are present.

Question

A reaction having time-independent stoichiometry follows the equation
A + 2B → 2Z
Suppose that initially there are present 0.28 moles if A, 0.39 moles of B and 0.13 moles
of Z.
After a certain amount of time, 0.18 moles of A remain. What amounts of B and
Z are present.

nottim · Answer

Any ideas?

michele_laino · Answer

hint:
at initial time, we have:
$$\Large  {n_A} = 0.28,\quad {n_B} = 0.39,\quad {n_C} = 0.13$$
and at final time, the same number of moles become:
$$\large {n_A} - x = 0.18,\quad {n_B} - x = 0.39 - 2x,\quad {n_C} + 2x = 0.13 + 2x$$
so we can write:
$$\Large 0.28 - x = 0.18$$
Please solve for $x$