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Mathematics 14 Online
OpenStudy (anonymous):

HELP WILL GIVE MEDAL

OpenStudy (anonymous):

The probability that an electronic device produced by a company does not function properly is equal to 0.1. If 10 devices are bought, then the probability, to the nearest thousandth, that 7 devices function properly is

OpenStudy (anonymous):

........................................................

OpenStudy (anonymous):

A. 0.057 B. 0.478 C. 0.001 D. 0

OpenStudy (michele_laino):

hint: I think that we can apply the binomial probability: \[\Large P = \left( {\begin{array}{*{20}{c}} {10} \\ 7 \end{array}} \right) \cdot {\left( {\frac{1}{{10}}} \right)^7} \cdot {\left( {\frac{9}{{10}}} \right)^3} = ...?\]

OpenStudy (jeansweets):

if I'm correct, p=729/7000000000

OpenStudy (triciaal):

@Michele_Laino question asked for the ones functioning properly . probability of each functioning properly is 9/10

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