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Use the diagram of the regular pentagon to support an explanation showing why the formula accurately yields the area of the pentagon. (Recall that a is the apothem and P is the perimeter of the pentagon.) A=1/2ap
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@Chiko_1278
If you divide up the hexagon into six congruent triangles and add up the areas of each triangle, then you will see that the formula makes sense. One-half the base of one of the six triangles times the apothem gives the area of one triangle. Adding this up six times, gives a/2( base + base + base + base + base + base). But the sum of the bases is the perimeter. So the area of the hexagon must be (a/2)(P)
It's not a hexagon though.....
would it still work?
hmm.. i think so
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