Question

can someone please check my answer to this question?
I will become a fan and will give a medal!
Question~
Solve the systems using the substitution method.
y = (2/3)x + 1
y + x = 6
My answer~
Solve one equation for ether variable ~
Y+x=6
=
In the other equation, replace the variable from S1 with what it equaled
(2/3)x+1+x=6
Solve the equation in step 2 for the other variable:
Multiply both sides by 3 to clear the fraction~ 3(2/3)x+1+x=6*3
Combine like terms~ 2x+3+3x=18
Subtract 3 from both sides~ 5x+3-3=18-3
Solve for x ~ 5x=15

Answer 1

yes, x = 3 and y = 3; your last answer is correct, but there are few typing mistakes

Answer 2

It'd be very much worth your while to learn how to check your own results in this kind of problem. If x = 3 and y = 3

... substitute those values into y = (2/3)x + 1
y + x = 6

... and determine whether both equations are true. If they are, you're correct.

Answer 3

Oh ok, @popitree could you tell me the typing mistake?

Answer 4

Your use of the " ~ " symbol is unusual (I would use : instead), but I don't consider this to be wrong.

Answer 5

ok thank you very much!!

Answer 6

:)