find the area
@DanJS
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The area of the original equilateral triangle equals the area of 6 of the small triangles.
One side of the small triangle is given. I called that side x. See figure above. The other side is \(\sqrt 3 x\). Multiply the given side by \(\sqrt 3\) to find the other side. Since theses two sides of the small triangle are at right angles to each other, they are a base and height. Multiply then together and divide by 2 to find the area of the small triangle. Then multiply that area by 6 to find the area of the large original triangle.
5400?
6 * 1/2 * root(3) * x * x 3*root(3)*x^2 use the length for x
\[3*\sqrt{3}*(\frac{ 8\sqrt{3} }{ 3 })^2\] \[64\sqrt{3}\approx 111 ~~unit^2\]
I think I understand now.... would this be 878?
@DanJS
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