Question

I need help on geometry!!!

Answer 1

Please present y our goals. What are you looking for here? What work have you done so far?

Answer 2

whats the question?

Answer 3

Find the missing side lengths. In this question, it would be to solve for \(x\).

Answer 4

I know that this is a 45-45-90 triangle and I also know that it has angle measures of
\(x\)-\(x\)-\(x\sqrt{2}\)

Answer 5

How would y ou find the length of the horiz. side?
Thank you for sharing your thoughts. What do you mean by "angle measures?" Are you certain that that's the correct terminology for this problem?

Answer 6

@mathmale I am sorry. But I am in a hurry to do these problems. Can you please explain these to me? I will look up the correct terminologies later, when I do have some spare time.

Answer 7

yeah start fillin er in,
bottom small triangle has sides 7-7-7root2

Answer 8

for a 45-45-90, if longest side is x, short side is x/sqrt(2)

Answer 9

and x/sqrt(2) is related to 7 in the same way

Answer 10

Some things can't be rushed. None of us can give you direct answers. If you have questions regarding what to do, ask those questions.

Answer 11

then the larger has sides 7root2-7root2 - 7 root2*root2

Answer 12

@mathmale This is why I am here to take help. I will understand the further details later. Thank you for understanding.

Answer 13

Sorry, but that's not the way OpenStudy works, and the same is true for any other situation in which you truly want to learn something for understanding.

Answer 14

@DanJS Would this be correct so far ?

Answer 15

yes, now do the same for bigger triangle, you need another root 2 for the slant side

Answer 16

Hints: Try breaking the problem down into steps. Find the hypotenuse of the smaller triangle. Yes, it is 7Sqrt(2). I'd be interested in knowing how you got that, however.

Answer 17

just have to remember the ratios of the sides here, 45-45-90 triangle, sides are same and the slant is root 2 of those sides

x - x - root2*x

Answer 18

@mathmale Well I know that we can use x-x-x\(\sqrt{2}\). since we already have the measure of one side being 7, then we can replace that for x and get \(7\sqrt{2}\)

Answer 19

@danjs: A reminder: Do NOT give away answers. You can give hints, but it is calculusxy who MUST do the work.

Answer 20

yeah yeah, i was explaining it,

Answer 21

@danjs. Please go back and read what I wrote y ou last time. These are the rules. Read the Code of Conduct if you've forgotten what it says. Thank you.

Answer 22

i need help on solving for that hypotenuse, because we know that the hypotenuse is x\(\sqrt{2}\). we claim that the x is 7\(\sqrt{2}\). so do i do \[7\sqrt{2} \times \sqrt{2} = 7 \times 2 = 14 \]

Answer 23

\[x-x-x \sqrt{_{2}}\] looks too much like subtraction, even though I do know what you're trying to do here.

Answer 24

The hyp of the smaller triangle is 7Sqrt(2). I agree with that.

Answer 25

sorry the x is not \(7\sqrt{2}\). it's one of the legs of the larger triangle

Answer 26

Now, that 7Sqrt(2) is one of the legs of the larger triangle, exactly as you say.

Answer 27

What is the length of the other leg of the larger triangle?

Answer 28

hmmmm, sure thing

Answer 29

And how would you (calculusxy) know the length of the other leg of the larger triangle?