Question

More help on geometry!

Answer 1

@mathmale

Answer 2

@DanJS

Answer 3

same idea here, what you get so far

Answer 4

the small triangle is x - x - x*root2 right

Answer 5

so i just checked out this short cut formula that tells me the shorter leg length:
\(\text{SL=}\frac{1}{2}\text{H}\)

SL is the length of the shorter leg
H is the hypotenuse

Answer 6

ill draw er up, you can reply with drawing

Answer 7

i did find SL and I got 9/2. how do i get it to the place where x is ?

Answer 8

do i continue to find 1/2 of 9/2 because 9/2 looks like the hypotenuse of the smaller triangle.

Answer 9

here is a little reference if you want
http://www.regentsprep.org/regents/math/algtrig/att2/ltri45.htm

the way i would do it is...

Answer 10

wow! i was looking at the 30-60-90!

Answer 11

small would be x - x - x*root2

therefore the large is, x*root2 - x*root2 - 9

right?

Answer 12

yes

Answer 13

apply the thing again, for the large

9 is root 2 times the side length

9 = (x*root2)*root2

Answer 14

and that gives you the x value you need

Answer 15

ok gimme a moment

Answer 16

k, you can reply with the drawing if you want

Answer 17

x = 9/2

Answer 18

yeah, you get what i did, just used the same ratio property a couple times

Answer 19

then the larger one gives you the slant side. The slant is root 2 times the side length, or 9 is root2 times x*root2